25y^2+20y+4=0

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Solution for 25y^2+20y+4=0 equation:


Simplifying
25y2 + 20y + 4 = 0

Reorder the terms:
4 + 20y + 25y2 = 0

Solving
4 + 20y + 25y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(2 + 5y)(2 + 5y) = 0

Subproblem 1

Set the factor '(2 + 5y)' equal to zero and attempt to solve: Simplifying 2 + 5y = 0 Solving 2 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5y = 0 + -2 5y = 0 + -2 Combine like terms: 0 + -2 = -2 5y = -2 Divide each side by '5'. y = -0.4 Simplifying y = -0.4

Subproblem 2

Set the factor '(2 + 5y)' equal to zero and attempt to solve: Simplifying 2 + 5y = 0 Solving 2 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5y = 0 + -2 5y = 0 + -2 Combine like terms: 0 + -2 = -2 5y = -2 Divide each side by '5'. y = -0.4 Simplifying y = -0.4

Solution

y = {-0.4, -0.4}

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